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You're trying to save to buy a new $210,000 Ferrari. You have $30,000 today that can be invested at your bank. The bank pays 5.0 percent annual interest on its accounts. How long will it be before you have enough to buy the car

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3 votes

Final answer:

To find out how many years it will take for $30,000 to grow to $210,000 at a 5% annual interest rate, we use the compound interest formula. By rearranging the formula to solve for the time variable t, we calculate it will take approximately 47.75 years to have enough to purchase the Ferrari.

Step-by-step explanation:

To determine how long it will take to save enough money to buy a new $210,000 Ferrari with an initial investment of $30,000 and an annual interest rate of 5%, we'll use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

  • A is the amount of money accumulated after n years, including interest.
  • P is the principal amount ($30,000).
  • r is the annual interest rate (decimal).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested or borrowed for, in years.

Since the bank pays interest annually, n will be 1. We need to solve for t when the amount A is $210,000:

$210,000 = $30,000(1 + 0.05/1)¹ˣ⁺

Rearranging the formula to solve for t, we have:

t = ln($210,000/$30,000) / ln(1 + 0.05)

Calculating this gives us:

t = ln(7) / ln(1.05)

Using a calculator, we find that t is approximately 47.75 years.

It will take almost 48 years for the initial $30,000 to grow to $210,000 at a 5% annual interest rate, assuming the interest is compounded annually and no additional deposits are made.

User Printfmyname
by
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5 votes

Answer:

39.88 years

Step-by-step explanation:

Given that

Future value = $210,000

Present value = $30,000

Annual rate of interest = 5%

As we know that

Future value = Present value × (1 + interest rate)^number of years

$210,000 = $30,000 × (1 + 0.05)^number of years

7 = (1 + 0.05)^number of years

After solving this, the number of years is 39.88 years

User Bmauter
by
3.5k points