Question

A plane crashes into the inside of a mountain if the crash place over 9 minutes and the planes velocity before the crash was 2000 yards per second what is the deceleration of the plane

Answer 1

The deceleration of the plane is
`3.38\ m/s^2`.

Step-by-step explanation:

Given that,

The planes velocity before the crash was 2000 yards per second

1 yards per second = 0.9144 m/s

2000 yards per second = 1828.8 m/s

Finally it crashes, its final speed will be 0.

It takes 9 minutes or 540 seconds. It will decelerate as the final speed is less than initial speed. So,

`a=(v-u)/(t)\\\\a=(0-1828.8)/(540)\\\\a=-3.38\ m/s^2`

So, the deceleration of the plane is
`3.38\ m/s^2`.