Question

A circular coil that has N = 290 N=290 turns and a radius of r = 11.5 cm r=11.5 cm lies in a magnetic field that has a magnitude of B 0 = 0.0705 T B0=0.0705 T directed perpendicular to the plane of the coil. What is the magnitude of the magnetic flux Φ B ΦB through the coil?

Answer 1

The magnitude of magnetic flux is 0.849 Wb.

Step-by-step explanation:

Given that,

Number of turns in a coil, N = 290

Radius of the coil, r = 11.5 cm

Magnetic field, B = 0.0705 T

The magnetic field is directed perpendicular to the plane of the coil. The magnetic flux is given by :

`\phi =NBA\\\\\phi =NB\pi r^2\\\\\phi =290* 0.0705 * \pi (11.5* 10^(-2))^2\\\\\phi=0.849\ Wb`

So, the magnitude of magnetic flux is 0.849 Wb.