Question

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 °C, if the amount of gas does not change?

Answer 1

The final volume of the bubble
`V_(2)` = 625 ml = 0.625 L

Step-by-step explanation:

`V_(1)` = 0.25 L = 250 ml

`P_(1)` = 2.4 atm

`T_(1)` = 15 °c = 288 K

`P_(2)` = 1 atm

`T_(2)` = 27 °c = 300 K

Mass of the gas is constant.

We know that

`P_(1) (V_(1))/(T_(1) ) = P_(2) (V_(2))/(T_(2) )`

Put all the values in above equation we get

`2.4 ((250)/(288) )= 1 ((V_(2) )/(300) )`

`V_(2)` = 625 ml = 0.625 L

This is the final volume of the bubble.