Question

Determine the total condensation rate of water vapor onto the front surface of a vertical plate that is 10 mm high and 1 m in the horizontal direction. The plate is exposed to saturated steam at atmospheric pressure and is maintained at 75oC.

Answer 1

Q = 63,827.5 W

Step-by-step explanation:

From the questions given, we recall the following,

The dimensions of vertical plate A = ( 10 mm x 1 m )

The fluid comes at T_sat, 1 atm.

The surface temperature pressure maintained T_s = 75°C

Thus we determine,

The total rate of condensation of water vapor onto the front surface of a vertical plate

Assuming drop-wise condensation the heat transfer coefficient for water is given by

Griffith's empirical relation for T_sat = 100°C.

Then

h = 255,310 W /m^2.K

The rate of condensation (Q) is stated by Newton's cooling law:

Q = h x As x ( T_sat - Ts )

Q = (255,310)x ( 0.01 x 1)x ( 100 - 75 )

Therefore

Q = 63,827.5 W

Answer 2

Q = 63,827.5 W

Step-by-step explanation:

Given:-

- The dimensions of plate A = ( 10 mm x 1 m )

- The fluid comes at T_sat , 1 atm.

- The surface temperature, T_s = 75°C

Find:-

Determine the total condensation rate of water vapor onto the front surface of a vertical plate

Solution:-

- Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.

h = 255,310 W /m^2.K

- The rate of condensation (Q) is given by Newton's cooling law:

Q = h*As*( T_sat - Ts )

Q = (255,310)*( 0.01*1)*( 100 - 75 )

Q = 63,827.5 W