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Write the equation of a parabola with vertex (2,-1) and directrix y=-3

User Dexa
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Answer:


y=-x^(2) -3x-3

Explanation:

a parabola is the graph of a quadratic equation, so the general equation is


y=ax^(2) +bx+c

If the directrix is negative, it means the graph opens down, so a is -

and c is -3

this gives us


y=-x^(2) +bx-3

all we need now is what is b

b is the y intercept for
y=mx+b

to find the y intercept, we plug in 0 for x


y=-x^(2) +bx-3\\y=-0^(2) +b(0)-3\\y=0+0-3\\y=-3

so the y intercept is -3

so the equation is


y=-x^(2) -3x-3

User Cojones
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