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A set of crash tests consists of running a test car moving at a speed of 10.8 m/s (24.2 mi/hr) into a solid wall. Strapped securely in an advanced seat belt system, a 57.0 kg (126 lbs) dummy is found to move a distance of 0.720 m from the moment the car touches the wall to the time the car is stopped. Calculate the size of the average force which acts on the dummy during that time.

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Answer:

The size of the average force which acts on the dummy during that time=4,617 N

Step-by-step explanation:

Initial Speed=u= 10.8 m/s

Final Speed=v=0 m/s

Mass=57 kg

distance=s=0.720 m

Required:

The size of the average force which acts on the dummy during that time=?

Solution:

According to 3rd equation of motion


v^2-u^2=2as


0^2-(10.8)^2=2*a*0.720

a=-81 m/s^2 (-ve sign for deceleration)

Note:

In calculating the force, we only use the magnitude of acceleration.

According to Newton's Second Equation:

F=ma

F=57*81

F=4,617 N

The size of the average force which acts on the dummy during that time=4,617 N

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