Answer:
Heterozygous, Yy
Step-by-step explanation:
According to Hardy-Weinberg equilibrium, the allele frequencies remain constant in a population in absence of an evolutionary force like genetic drift or natural selection. Since here the population is under low selective pressure, it can be considered almost in Hardy-Weinberg equilibrium. According to it,
p + q = 1
p² + 2pq + q² = 1 where,
p = frequency of dominant allele = f(Y)
q = frequency of recessive allele = f(y)
p² = frequency of homozygous dominant genotype = f(YY)
2pq = frequency of heterozygous genotype = f(Yy)
q² = frequency of homozygous recessive genotype = f(yy)
Hence, the term 2pq represents the frequency of heterozygous Yy peas.