Question

For what value(s) of p will the equation x^2=p have 2 real number solutions? Explain your reasoning?

Answer 1

p > 0

Explanation:

x² = p

x² - p = 0

A = 1, B = 0, C = -p

For 2 real roots:

B² - 4AC > 0

0² - 4(1)(-p) > 0

4p > 0

p > 0