Question

How many moles are in a 501mL of a 2.37 M solution of Al2(SO4)3?

Answer 1

The number of moles of Al₂(SO₄)₃ is 1.2 mol

Step-by-step explanation:

Given:

Volume of the solution, V = 501 mL

V = 0.501L

Molarity of the solution, M = 2.37M

Moles, n = ?

We know:

Molarity =
`(moles of solute)/(volumeof solution)`

On substituting the values we get:

`2.37 = (n)/(0.501) \\\\n = 1.2 mol`

Therefore, the number of moles of Al₂(SO₄)₃ is 1.2 mol