Question

Air enters a compressor operating at steady state at 1 atm with a specific enthalpy of 290 kJ/kg and exits at a higher pressure with a specific enthalpy of 1023 kJ/kg. The mass flow rate is 0.1 kg/s. Kinetic and potential energy effects are negligible and the air can be modeled as an ideal gas. If the compressor power input is 77 kW, the rate of heat transfer between the air and its surroundings is

Answer 1

To calculate the rate of heat transfer between air and its surroundings, use the equation Q = mcΔT.

Step-by-step explanation:

In this question, we are asked to calculate the rate of heat transfer between air and its surroundings. To find this, we need to use the equation Q = mcΔT, where Q is the heat transfer, m is the mass of the air, c is the specific heat of air, and ΔT is the change in temperature.

We are given the specific enthalpy of air at the inlet and outlet of the compressor, as well as the mass flow rate of the air. Using this information, we can find the change in temperature and calculate the rate of heat transfer.