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A 50 g dart rests up against a spring that has been compressed 0.04 meters. It has a spring constant of 1560 N/m.What is the maximum velocity of the dart after the spring has transferred all its energy to it.

User FreeOnGoo
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Answer:

The maximum velocity of the dart after the spring has transferred all its energy to it is 7.06 m/s.

Step-by-step explanation:

Given that,

Mass of the dart, m = 50 g = 0.05 kg

Compression in the spring, x = 0.04 m

Spring constant, k = 1560 N/m

We need to find the maximum velocity of the dart after the spring has transferred all its energy to it. The kinetic energy is converted to elastic potential energy as :


(1)/(2)mv^2=(1)/(2)kx^2


v=\sqrt{(kx^2)/(m)} \\\\v=\sqrt{(1560* (0.04)^2)/(0.05)} \\\\v=7.06\ m/s

So, the maximum velocity of the dart after the spring has transferred all its energy to it is 7.06 m/s.

User Systemjack
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