Answer:
0.1175 or 11.75%
Explanation:
If the new machine is 3 times more productive than the old machine, then 75% of widgets are produced by the new machine with a defective rate of 8%, while 25% of widgets are produced by the old machine with a defective rate of 23%.
The probability that a randomly chosen widget produced by the company is defective is given by:
![P = 0.75*0.08+0.25*0.23\\P=0.1175=11.75\%](https://img.qammunity.org/2021/formulas/mathematics/college/htu1s8n6zy0f5yog0x75161xbir3x0hl40.png)
The probability is 0.1175 or 11.75%.