Question

To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.663 m from rest?

Answer 1

3.6 m/s

Step-by-step explanation:

We are given that

Initial velocity of free falling body,u=0

Distance, h
`=0.663 m`

We have to find the velocity of an untethered stone after falling 0.663 m

`v^2-u^2=2gh`

Where
`g=9.8m/s^2`

Substitute the values

`v^2-0=2* 9.8* 0.663`

`v=√(2* 9.8* 0.663)`

`v=3.6 m/s`

Hence, the velocity of an untethered stone after falling 0.663 m=3.6 m/s