Question

cIn a traction drive, a 1.4-in.-diameter cylindrical roller is preloaded against a 3.4-in. diameter cylindrical roller. The steel rollers are 3.7 in. wide and the preload force is 56 lb. The axes of the cylinders are parallel. Calculate the maximum contact pressure in ksi.

Answer 1

The maximum contact pressure is 12.658 ksi

Step-by-step explanation:

The contact modulus is:

Δ = M

`M=2*((1-v^(2) )/(E) )=2*((1-0.3^(2) )/(30x10^(6) ) )=6.06x10^(-8) in^(2) /lb`

The radius of curvature is:

r1 = D1/2 = 1.4/2 = 0.7 in

r2 = D2/2 = 3.4/2 = 1.7 in

The maximum contact pressure is:

`P=0.564\sqrt{(F*((1)/(r_(1) )+(1)/(r_(2) )) )/(L*M) } =0.564\sqrt{(56*((1)/(0.7)+(1)/(1.7)) )/(3.7*6.06x10^(-8) ) } =12658.09psi=12.658ksi`