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A constant current charges a 20-nanofarad [nF) capacitor to 5 volts [V] in 10 microseconds [us]. (a) Determine the current. Express your answer in units of amperes, using an appropriate metric prefix

User Fou
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1 Answer

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Answer:

Current in the capacitor will be equal to 0.01 A

Step-by-step explanation:

Capacitance of the capacitor
C=20nF=20* 10^(-9)F

Capacitor voltage is change to 5 volt

So change in capacitor voltage
dV=5volt

Time taken to change in capacitor voltage
dt=10\mu sec=10^(-5)sec

Current in the capacitor is equal to


i=C(dV)/(dt)=20* 10^(-9)* (5)/(10^(-5))=0.01A

So current in the capacitor will be equal to 0.01 A

User Pratik Deoghare
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