Question

A rocket in the shape of acone is attached to a cylinder with the same base radius the cone has aslant height of 15m the cylinder has abase diameter of 12m and a height of 42m find the total surface area of the rocket

Answer 1

the total surface area of the rocket: 1978.2
`m^(2)`

Explanation:

Given that :

• A rocket in the shape of a cone
• The aslant height: 15m
• The base diameter: 12m <=.> Radius: 6m
• The height: 42

So the surface area of a a cone with about the base area because it is attached to a cylinder:

= π*r*l = 3.14*6*15 = 282.6
`m^(2)`

The area of the cylinder is: 2*π*r*h+pi*
`r^(2)` (without the top part of it)

= 2*3.14*6*42 + 3.14*
`6^(2)`

= 1695.6
`m^(2)`

At the end, the total surface area of the rocket:

1695.6
`m^(2)` + 282.6
`m^(2)` = 1978.2
`m^(2)`