Answer:
![f=1280Hz](https://img.qammunity.org/2021/formulas/physics/college/xe0k48frhwmq11uaav9uukohh9xskuhrua.png)
Step-by-step explanation:
In physics, wavelength is the distance traveled by a periodic disturbance that propagates through a medium in one cycle. the wavelength, the frequency and the propagation speed, are linked together by the following mathematical relationship:
![\lambda=(v)/(f)](https://img.qammunity.org/2021/formulas/physics/college/hq71kygldddou7o0fxc9o4re7sdzltb1pg.png)
Where:
![\lambda=wavelength=2cm=0.02m\\v=propagation\hspace{3} speed=25.6m/s\\f=frequency](https://img.qammunity.org/2021/formulas/physics/college/z08th0k13si5tlb0v1s6ovwn5q1y999hwo.png)
Solving for
:
![f=(v)/(\lambda) =(25.6)/(0.02)=1280Hz](https://img.qammunity.org/2021/formulas/physics/college/mz2xjsclgez0g6n96lusz86pavxcjjprrh.png)
Therefore the frequency of these vibrations is 1280 Hz.