Answer:
We will produce 57.1 grams of silver sulfadiazine
Step-by-step explanation:
Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly into the wound. If 20.0 g of Ag2O is reacted with 40.0 of C10H10N4SO2, what mass of silver sulfadiazine (AgC10H9N4SO2) can be produced assuming 100% yield?
Step 1: Data given
Mass of Ag2O = 20.0 grams
Molar mass of Ag2O = 231.735 g/mol
Mass of C10H10N4SO2 = 40.0 grams
Molar mass of C10H10N4SO2 = 250.277 g/mol
Step 2: The balanced equation
Ag2O + 2C10H10N4SO2 → 2AgC10H9N4SO2 + H2O
Step 3: Calculate moles Ag2O
Moles Ag2O = mass Ag2O / molar mass Ag2O
Moles Ag2O = 20.0 grams / 231.735 g/mol
Moles Ag2O = 0.0863 moles
Step 4: Calculate moles C10H10N4SO2
Moles C10H10N4SO2 = 40.0 grams / 250.277 g/mol
Moles C10H10N4SO2 = 0.160 moles
Step 5: Calculate the limiting reactant
For 1 mol Ag2O we need 2 moles 2C10H10N4SO2 to produce 2 moles AgC10H9N4SO2 and 1 mol H2O
C10H10N4SO2 is the limiting reactant. There will react 0.160 moles.
Ag2O is in excess. There will react 0.160/ 2 = 0.080 moles
There will remain 0.0863 - 0.080 = 0.0063 moles Ag2O
Step 5: Calculate moles AgC10H9N4SO2
For 1 mol Ag2O we need 2 moles 2C10H10N4SO2 to produce 2 moles AgC10H9N4SO2 and 1 mol H2O
For 0.160 moles C10H10N4SO2 we'll have 0.160 moles AgC10H9N4SO2
Step 6: Calculate mass AgC10H9N4SO2
Mass AgC10H9N4SO2 = moles * molar mass
Mass AgC10H9N4SO2 = 0.160 moles * 357.137 g/mol
Mass AgC10H9N4SO2 = 57.1 grams
We will produce 57.1 grams of silver sulfadiazine