Question

M is the midpoint of PQ. The diameter of circle O is 15 in. and RM = 3 in.

Answer 1

PM=6 inches

PQ=12 inches

Explanation:

-The product of the segments of chords that intersect within a circle are always equal.

`RM.MS=PM.MQ`

Given that PM=MQ and RS=15(MS=15-3=12):

`RM.MS=PM.MQ\\\\12* 3=PM^2=MQ^2\\\\36=PM^2\\\\PM=MQ=6\ in \\\\PQ=PM+MQ=2* 6=12\ in`

Hence, the length PM is 6 inches and PQ is 12 inches