Question

A large aquarium of height 5 m is filled with fresh water to a depth of D = 2.20 m. One wall of the aquarium consists of thick plastic with horizontal length w = 8.20 m. By how much does the total force on that wall increase if the aquarium is next filled to a depth of D = 4.40 m? (Note: use g = 9.81 m/s2 and rho = 998 kg/m3.)

Answer 1

`P=21538.836\ Pa`

Step-by-step explanation:

Given:

Initial depth of water in the aquarium,
`D_i=2.2\ m`

width of a wall of aquarium,
`w=8.2\ m`

final depth of the water in the aquarium,
`D_f=4.4\ m`

Now the change in pressure on the wall:

`P=\rho.g.(D_f-D_i)`

`P=998* 9.81* (4.4-2.2)`

`P=21538.836\ Pa`