Question

You are given a straight piece of conductor that is 5.5 cm long and moves in a region of uniform magnetic field of 1.7 T along the z-direction. If the conductor is oriented along the x-axis and moves in the y-direction with a velocity of 4.0 m/s, find the magnitude of induced voltage that will be produced between the ends of this moving conductor.

Answer 1

e=0.374V

Step-by-step explanation:

the induced voltage is the work done per unit of charge. Hence we have

`\epsilon=(W)/(q)=(FL)/(q)=(qvBLsin\theta)/(q)`

however, the angle between the piece of conductor and the field is 0°. Hence

`\epsilon=vBL=(4.0(m)/(s))(1.7T)(0.055m)=0.374V`

THE INDUCED VOLTAGE IS 0.374V

hope this helps!!