Complete question is in attachment
Answer:
a) scenario 1 and 3 will have the highest flow rate with 12p/hr
b) scenario 3 will have the lowest flow time of 9 mins
Step-by-step explanation:
a) let's compute the flow rate ot the 3 scenarios.
We now have:
•For scenario 1:
Processing time of workstation A = 5mins
Processing time of workstation B = 5mins
Therefore, the cycle time of process= max(processing time of A, processing time of B)
=> max(5,5)
=5 mins
flow rate= 1/cycle time
= 1/5 per minute
Convert to hrs we have:
(1*60)/5 = 12per hour
•For scenario 2
Consider the 50℅ probability that processing time of workstation B is 4mins:
Processing time of workstation A = 5mins
Processing time of workstation B = 5mins
Therefore, the cycle time of process= max(processing time of A, processing time of B)
=> max(5,4)
= 5mins
flow rate= 1/cycle time
= 1/5 per minute
Convert to hrs we have:
(1*60)/5 = 12per hour
Let's now consider the 50℅ probability that processing time of workstation B is 6mins
= max(5,6)
=6 mins
flow rate= 1/6 per minute
= (1*60)/6 = 10per hour
Therefore, expected flow rate = 50℅*12+50℅*10= 11hours
•For scenario 3:
Processing time of workstation A = 5mins
Processing time of workstation B =either 3 or 5mins
Therefore, the cycle time of process= max(processing time of A, processing time of B)
=> max(5, 3 or 5)
= 5mins
flow rate= 1/cycle time
= 1/5 per minute
Convert to hrs we have:
(1*60)/5 = 12per hour
Therefore scenario 1 and3 have highest flow rate with 12per hour
b) We find the time rate by adding up the processing time.
•For scenario 1:
Processing time of workstation A = 5mins
Processing time of workstation B= 5mins
Therefore flow time will be= 5+5 = 10mins
For scenario 2:
Processing time of workstation A = 5mins
Processing time of workstation B has 50℅ chance of being 4 mins and anothe 50℅ of being 6mins
Therefore processing time of B will be= 50%*4+50%*6= 5mins
Therefore, flow time = 5+5= 10mins
•For scenario 3:
Processing time of workstation A = 5mins
Processing time of workstation B has 50℅ chance of being 3mins and anothe 50℅ of being 5mins
Therefore processing time of B will be= 50%*3+50%*5= 4mins
Therefore, flow time = 5+4= 9mins
Therefore, scenario 3 has lowest flow time with 9mins