Question

an IPv6 packet has a 40 byte base header, a 20 byte destination options extension header (which is not used for routing) and 2000 bytes of payload data (total packet length is 2060 bytes). This is to be fragmented to travel over a network with a MTU of 1500 bytes. Considering the fragmentable and unfragmentable parts of this packet, create a sketch showing the headers and data in each fragment, including the number of bytes. Don’t forget the fragmentation header, which is 8 bytes.

Answer 1

Step-by-step explanation:

Given, total payload is: 2000 bytes

MTU is: 1500 bytes

Header is: 20 bytes

Base header is: 40 bytes

Total number of fragments = Total Payload / MTU

= 2500 / 1500

= 2 fragments

Fragment Base header Fragmentation header Authentication

header + Data

1 40 bytes 8 bytes 20 bytes +772bytes

2 40 bytes 8 bytes 792 bytes