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What is the true solution to 2 l n e Superscript l n 5 x Baseline = 2 l n 15

x = 0
x = 3
x = 9
x = 15

What is the true solution to 2 l n e Superscript l n 5 x Baseline = 2 l n 15 x = 0 x-example-1
User Rychu
by
8.5k points

2 Answers

3 votes

Answer:

B: x = 3

Explanation:

cause i said so.

User Cat Perry
by
7.9k points
4 votes

Answer:

(b) x = 3

Explanation:

The equation can be simplified by using the fact ...

ln(e^x) = x

This gives ...

2·ln(5x) = 2·ln(15)

Comparing arguments, we see ...

5x = 15

x = 3 . . . . . divide both sides by 5

_____

If you want to check this, you can find the numbers at each stage of evaluation.

2·ln(e^(ln(5·3))) = 2·ln(15)

2·ln(e^2.70805) = 2·2.70805

2·ln(15) = 5.41610

2·2.70805 = 5.41610 . . . . . true

User Evilsanta
by
7.7k points

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