Question

Calculate the impulse of a 0.140 kg baseball that starts at rest on a tee and reaches a final velocity of 20 m/s after being struck with a force of 100 N.

Answer 1

Step-by-step explanation:

impulse = change in momentum

F×t =m(v-u)

I = 0.140(20-0)

I = 0.140 × 20

I = 2.8NS

Answer 2

Answer: 2.8 Ns

Step-by-step explanation:

Given that,

impulse I = ?

Mass of baseball M = 0.140 kg

Initial velocity (at rest) Vi = 0m/s

final velocity Vf = 20 m/s

force F = 100 N

Recall that impulse is the product of force and the time during which it acts

i.e Impulse = Force x Time

(since impulse is also equal to change in momentum, then

impulse = Ft = M x (Vf - Vi)

So, apply I = M x (Vf - Vi)

I = 0.140kg x (20 m/s - 0 m/s)

I = 0.140kg x (20 m/s)

I = 2.8 Ns

Thus, the impulse of the baseball is 2.8 Ns