Question

Arrange the elements in each set in order of decreasing electronegativity (enter with no spaces e.g. N>P>Si):

I. N>P>Si N, P, Si
II. As>Ga>Ca Ca, Ga, As
III. Cl>Br>P Br, Cl, P IV. F>O>I I ,F,O

Answer 1

Answer: In order of decreasing electronegativity (that is, from highest to lowest)

1. N > Si > P
2. As > Ga > Ca
3. P > Cl > B
4. O > F > I

Step-by-step explanation:

Electronegativity is the ability of an atom in a compound to attract and bind with electrons in order to form a chemical bond. Across the period from left to right (on the periodic table), electronegativity increases, whilst it decreases down the group. The only exceptions to this rule are lanthanides, actinides and noble gases.

Answer 2

Step-by-step explanation:

The trend of electronegativity in the periodic table is given as;

The electronegativity of atoms increases as you move from left to right across a period in the periodic table. The electronegativity of atoms decreases as you move from top to bottom down a group in the periodic table.

I. N, P, Si

N is in period 2 while P and Si are both in period 3. N has the greatest electronegativity aamong the three. Since electronegativity increases from left to right in a period, P has a greater electronegativity than Si. The trend is given as; N>P>Si

II. Ca, Ga, As

Since electronegativity increases from left to right in a period, As has the highest electronegativity because it is in group 5 period 4, followed by Ga which is in group 3 period 5, then the least which is Calcium present in group 2, period 5. The trend is given as; As>Ga>Ca

III. Br, Cl, P

Since electronegativity increases from left to right in a period, Cl has the highest value. Bromine has a higher value of electronegativity because it is a group 7 element. The least electronegative is P. The trend is given as; Cl>Br>P

IV. I ,F,O

Fluorine is the most electronegative element. Followed by oxygen. The electronegativity of atoms decreases as you move from top to bottom down a group in the periodic table. The least is Iodine, the trend is given as; F>O>I