Question

Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal polarizing filter whose axis is at 45.0 ∘∘ to that of the first. Part A Determine the intensity of the beam after it has passed through the second polarizer. Enter the factor only. For example, enter 0.2500.250, that means your answer is I=0.250I0I=0.250I0. II = nothing I0I0 SubmitRequest Answer Part B Determine its state of polarization. Determine its state of polarization. The light is linearly polarized along the axis of the first filter. The light is linearly polarized along the axis of the second filter. The light is linearly polarized perpendicular to the axis of the second filter. The light is linearly polarized perpendicular to the axis of the first filter. SubmitRequest Answer Provide Feedback

Answer 1

A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

Step-by-step explanation:

A) Light passing through a polarizer must comply with the / bad law

I = Io cos2 tea

Where is at the angle of the polarizer and incident light

I = Io cos2 45

I = Io 0.578

Therefore the beam intensity is 0.578 of the incident intensity

.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter