As here we are given with an equilateral triangle, whose side is 3 cm, and we need to find the height and area of the equilateral triangle. So, for this let's recall that, the area of any equilateral triangle with side a is given by ;
So, if we substitute a = 3, in our Formula, it will yield to
![{:\implies \quad \sf Area_((Equilateral\:\:Triangle))=(√(3))/(4)(3)^(2)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/q57op49vyxwl1cczprjf7hqj26vgg7g55z.png)
![{:\implies \quad \sf Area_((Equilateral\:\:Triangle))=(√(3))/(4)(9)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qwyrwmjvrdjxgu3oj1gpxpzohicy8fzl5r.png)
![{:\implies \quad \boxed{\bf{Area_((Equilateral\:\:Triangle))=(9√(3))/(4)\:\:cm^(2)}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2xphqe3nsdebo2ib2p81xs6esq4i5ly7lk.png)
Now, as we know that, for any triangle we also have a formula that is ;
Now, Here as the triangle is equilateral, so it's base will just be same 3, and if we let height be H, so we will be having
![{:\implies \quad \sf (1)/(2)* 3* H=(9√(3))/(4)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/50jenkttqvudu9y74vr04nr40q8pb578tj.png)
![{:\implies \quad \sf H=(9√(3))/(4)* \frac23}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3rkhxo0gh5vgresvk31ta6vksaj4dlx0yg.png)
![{:\implies \quad \boxed{\bf{Height=(3√(3))/(2)\:\:cm}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/rn5v6ollswafdh2glyi5w54bclsnie53kf.png)