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A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s. What is the magnitude of the change in linear momentum of the ball?

User Gemini
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1 Answer

6 votes

Answer:

The magnitude of the change in linear momentum of the ball is 6 kg-m/s.

Step-by-step explanation:

Given that,

Mass of the ball, m = 1 kg

Initial sped of the ball, u = 3 m/s

It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s

The magnitude of the change in linear momentum of the ball is given by :


p=m(v-u)\\\\p=1\ kg* (-3-3)\\\\p=-6\ kg-m/s

So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.

User Karellm
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