Final answer:
To find the closest volume of the remaining water in the cylindrical tank, first calculate the full tank's volume using the radius (half of the diameter which is 11 feet) and height (9.5 feet), then find 6/7 of that volume to account for the water consumed. The approximate remaining water volume is 775.79 cubic feet.
Step-by-step explanation:
The question requires us to find the volume of water remaining in a cylindrical tank after some has been consumed. First, we calculate the tank's diameter, which is 1.5 feet longer than its height, so the diameter is 9.5 feet + 1.5 feet = 11 feet. The radius is half of the diameter, so it is 11 feet / 2 = 5.5 feet. Next, we calculate the full tank's volume using the formula for the volume of a cylinder, V = πr²h. Plugging in the values, we get V = π * (5.5 feet)² * 9.5 feet. As someone consumed one-seventh of the water, the volume of the remaining water is 6/7 of the full volume. To find this, we calculate (6/7) * π * (5.5 feet)² * 9.5 feet.
To provide an approximation, we can use π = 3.14. Thus, the full volume is approximately 3.14 * (5.5 feet)² * 9.5 feet = 3.14 * 30.25 feet² * 9.5 feet ≈ 904.09 cubic feet. The volume of the remaining water is (6/7) * 904.09 cubic feet ≈ 775.79 cubic feet. This is the closest volume of the remaining water in the tank.