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You’ve just started a new job in the laboratory of the Food and Drug Administration. Your supervisor asks you to prepare a 1.50-M solution of aqueous potassium permanganate, KMnO4. What mass of KMnO4 will you need to prepare 500 mL of this solution?

1 Answer

2 votes

Answer: 118.5 grams

Step-by-step explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.


Molarity=(n* 1000)/(V_s)

where,

n= moles of solute


V_s = volume of solution in ml = 500 ml


1.50=(moles* 1000)/(500ml)

moles = 0.75

moles of solute =
\frac{\text {given mass}}{\text {molar mass}}

0.75 =
\frac{\text {given mass}}{158g/mol}

mass of
KMnO_4 = 118.5 grams

Thus mass of
KMnO_4 needed to prepare 500 mL of this solution iis 118.5 grams

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