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What are the solutions of x^2 + 10x+16=0

2 Answers

3 votes

x^2+8x+2x+16=0

or,x(x+8)+2(x+8)=0

or,(x+2)(x+8)=0

therefore,

x=-2,-8

User Latisha
by
4.7k points
3 votes

Answer:

x=−2,−8

Explanation:

Move terms to the left side. Then set each factor equal to zero.

x=−2,−8

User Ken Bloom
by
4.8k points