Answer:
= ( 1.08 / 2.2 ) 100% = 49%
Step-by-step explanation:
Balanced Equation: 2CH₃CH₃(g) + 5O₂(g) → 2CO₂(g) + 6H₂O(g)
Calculate moles of CH₃CH₃ and O₂
1.2 ₃₃ ( 1 ₃₃/ 30.0694 ₃₃ ) = 0.040 ₃₃
8.6 ₂ ( 1 2/ 31.998 ₂ ) = 0.27 ₃₃
Find limiting reagent 0.040 ₃₃ ( 5 ₂/ 2 ₃₃ ) = 0.10 ₂
CH₃CH₃ is the limiting Reagent
CH₃CH₃ (L.R.) O₂ CO₂ H₂O
Initial (mol) 0.040 0.27 0 0
Change (mol) -2x=-0 -5x= -0.10 +2x=+0.040 +6x=+0.12
Final (mol) 0 0.117 0.040 0.12
0.040 − 2 = 0 = 0.020
Determine percent yield
0.12 ₂ ( 18.0148 ₂ /1 ₂ ) = 2.2 ₂
= ( 1.08 / 2.2 ) 100% = 49%