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There are 3 children of a lady. In how many ways is it possible to dress them for a party if the first child likes 3 dresses, second likes 4 and the third likes 5 but the third child has out grown one of them? Each child has a different set of clothes.

A. 11
B. 10
C. 60
D. 48
E. 15

ty!

User HunterLion
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1 Answer

21 votes
21 votes

If all of their dresses are fit for the kids, the possible way to dress them is 3*4*5=60

But one dress is out grown for the third child. Hence, the combination that are not possible.

3*4*1=12

So total number of possible ways are :

3*4*5 - 3*4*1=48

Hence the answer is option D.

User Whp
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