Question

The molecular weight of sucrose, \text{C}_{12} \text H_{22} \text O_{11}C 12 ​ H 22 ​ O 11 ​ start text, C, end text, start subscript, 12, end subscript, start text, H, end text, start subscript, 22, end subscript, start text, O, end text, start subscript, 11, end subscript, is 342.30\,\dfrac{\text g}{\text{mol}}342.30 mol g ​ 342, point, 30, start fraction, start text, g, end text, divided by, start text, m, o, l, end text, end fraction. What is the mass, in grams, of 0.0287\,\text {mol}0.0287mol0, point, 0287, start text, m, o, l, end text of sucrose? Express the answer using 3 significant figures.

Answer 1

This sample of sucrose has a mass of 9.82 grams

Step-by-step explanation:

Step 1: Data given

The molecular weight of sucrose = 342.30 g/mol

The number of moles of this sucrose sample = 0.0287 moles

Mass = moles * molar mass

Step 2: Calculate the mass of this sucrose sample

Mass sucrose = moles sucrose * molar mass sucrose

Mass sucrose = 0.0287 moles * 342.30 g/mol

Mass sucrose = 9.82401‬ grams

When we express this amount using 3 significant figurse we have:

Mass sucrose = 9.82 grams

This sample of sucrose has a mass of 9.82 grams