Question

Help me pleaseee i need it baddd

Answer 1

Answer: D

Explanation:

`x^2-3x+3=0\qquad \rightarrow \qquad a=1,\ b=-3,\ c=3\\\\\\x=(-b\pm √(b^2-4ac))/(2a)\\\\\\x=(-(-3)\pm √((-3)^2-4(1)(3)))/(2(1))\\\\\\x=(3\pm √(9-12))/(2)\\\\\\x=(3\pm √(-3))/(2)\\\\\\x=(3\pm i√(3))/(2)\\\\\\\boxed{x=(3+ i√(3))/(2)\qquad \qquad x=(3- i√(3))/(2)}`