Answer:
a) y² = (1/3) x³ (Pic 1)
y² = (1/3) x³ + 1 (Pic 2)
b) The streamlines are shown in the pics.
c) The stream function is used to plot the streamlines of the flow (which represent the trajectories of particles in a steady flow) and find the velocity.
d) V = 2y i + x² j
e) This flow does not satisfy conservation of mass.
Step-by-step explanation:
Given
u = 2y
v = x²
a) So the streamlines are given by
dy/dx = v/u = x²/2y
Thus
∫2ydy = ∫x²dx
⇒ y² = (1/3) x³ + C
where C is a constant.
For the streamline that goes through x = y = 0, C = 0
Hence
y² = (1/3) x³
For the streamline that goes through x = 0 and y = 1,
(1)² = (1/3) (0)³ + C = 0
⇒ C = 1
Hence
y² = (1/3) x³ + 1
b) The streamlines are plotted in the pic shown.
c) Stream functions are defined for two-dimensional flow and for three-dimensional axial symmetric flow. The stream function is used to plot the streamlines of the flow (which represent the trajectories of particles in a steady flow) and find the velocity.
d) V = 2y i + x² j
e) We apply ∇V = 0
then
∇V = ∂V/∂x + ∂V/∂y + ∂V/∂z
⇒ ∇V = (0, 2x, 0) + (2, 0 , 0) + (0, 0, 0) = (2, 2x, 0) ≠ 0
This flow does not satisfy conservation of mass.