complete question:
Two students in a behavioral sciences class compared their scores on a series of five quizzes. Which student tended to perform better on the quizzes? Which student tended to perform more consistently on the quizzes?
student x : 4, 9, 3, 8, 9
student y : 6, 5, 7, 5, 6
Answer:
a. We can conclude that student x perform better than student y in the quizzes.
b. Student y tend to perform more consistently on the quizzes.
Step-by-step explanation:
Which student tended to perform better on the quizzes?
Using the mean score we can know the student that performs better. Therefore let's calculate the mean of each student.
student x
mean = 4 + 9 + 3 + 8 + 9/5 = 33/5 = 6.6
student y
mean = 6 + 5 + 7 + 5 + 6/ 5 = 29/5 = 5.8
We can conclude that student x perform better than student y in the quizzes.
b. Which student tended to perform more consistently on the quizzes?
Student y tend to perform more consistently on the quizzes. There is more homogeneity in the score of student y and more heterogeneity in the score of student x. The score of student x range from 3 to 9, so it covers more range while student y score range from 5 to 7 which is more consistent.