161k views
1 vote
A 13-N weight and a 12-N weight are connected by a massless string over a massless, frictionless pulley. The 13-N weight has a downward acceleration with magnitude equal to that of a freely falling body times:

A. 1
B. 1/12
C. 1/13
D. 1/25
E. 13/25

1 Answer

3 votes

Answer:

D

Step-by-step explanation:

We are given that

Weight,
w_1=13 N


w_2=12 N

We have to find the acceleration of 13 N weight .


m_1=(w_1)/(g)=(13)/(g)kg


m_2=(w_2)/(g)=(12)/(g) kg

Net force,
w_1-w_2=13-12=1 N

Total mass,
m=m_1+m_2=(13)/(g)+(12)/(g)=(25)/(g)kg

Acceleration,
a=(Net\;force)/(total\;mass)

Using the formula


a=(1)/((25)/(g))=(1)/(25)g

Where g=Acceleration due to gravity

Hence, option D is true.

User Leaha
by
5.7k points