26.3k views
2 votes
The area of a rectangle is

(x2 + 17x+42) ft?
If its width is (x + 3) ft.
What is its length?

2 Answers

0 votes

Answer:

Explanation:

area= L×W

L×(x+3)= x²+17x+42

L×(x+3)= (x+3)(x+14)

by dividing (x+3) from both sides

∴ L=(x+14)

User Ahi
by
7.4k points
3 votes

Answer:

( x + 14) ft

Explanation:


length \: of \: rectangle = (area \: of \: rectangle)/(width \: of \: rectangle) \\ \\ = \frac{ {x}^(2) + 17x + 42}{x + 3} \\ \\ = \frac{ {x}^(2) + 14x + 3x + 42}{x + 3} \\ \\ = \frac{ x({x} + 14) + 3(x + 14)}{x + 3} \\ \\ = \frac{ ({x} + 14) (x+ 3)}{x + 3} \\ \\ = x + 14 \\ \therefore \: length \: of \: rectangle =( x + 14) \: ft

User Sistina
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories