Question

In an LC circuit containing a 40-mH ideal inductor and a 1.2-mF capacitor, the maximum charge on the capacitor is 45 mC during the oscillations. What is the maximum current through the inductor during the oscillations?

Answer 1

6.49A

Step-by-step explanation:

Given the following parameters

Inductance L = 40mH

Capacitance C = 1.2mF

Maximum charge on the capacitor Q = 45 mC

The current across the inductor can be expressed as I = charge on the capacitor × angular frequency

I = Qω where

ω = 1/√LC

I = Q × 1/√LC

I = Q/√LC

Substituting the given datas into the maximum current formula will give;

I = 45 x 10⁻³/√(40×10⁻³×1.2×10⁻³)

I = 45 x 10⁻³/√48 x 10^-6

I = 45 x 10⁻³/0.00693

I = 0.045/0.00693

I = 6.49A