Complete Question:
attached
Answer:
B, A, C
Step-by-step explanation:
We will first calculate the stress for each sample :
σ_m = σ_max+σ_min/2
σ_ma = 450-150/2 = 150 Mpa
σ_mb = 300-300/2 = 0 Mpa
σ_mc = 500-200/2 = 150 Mpa
Now calculate the stress amplitudes:
σ_a = σ_max-σ_min/2
σ_aA = 450+150/2 = 350 Mpa
σ_aB = 300+300/2 = 300 Mpa
σ_aC = 500+200/2 = 350 Mpa
Specimen B will have the longest fatigue life because it has the smallest mean stress. Next comes specimen A and finally specimen C. C is last because it has the highest stress amplitude and ties for the highest mean stress. B, A, C