Question

Translate the following C program into an assembly program. The C program finds the minimal value of three signed integers. Assume a, b, and c is stored in register r0, r1, and r3 respectively. The result min is saved in register r4. If (a< b && a

Answer 1

See explaination

Step-by-step explanation:

Written below is the ARM assembly code for finding minimum amongst three numbers

;Please use Keil uvison for running the code

;should include a,b and c values

GLOBAL minimum

AREA MYCODE, CODE, READONLY

ENTRY

minimum

MOV r0, #0xA ;value of a load into r0

MOV r1, #0x3 ;value of b load into r1

MOV r3, #0x8 ;value of c load into r3

CMP r0,r1 ; Compare value in r0 with r1 i.e a < b

BLT less1 ; if value of r0 < value of r1 then branch to less1 Else next instruction

CMP r1,r0 ;compare value in r1 with r0 i.e b < a

BLT less2 ;branch if r1<r0 to less2

MOV r4,r3 ; copy result into r4 else condiiton min=c

less1 ;less1 routine

CMP r0,r3 ;a < c

BLT cond1

less2 ;less2 routine

CMP r1,r3 ;b < c

BLT cond2

cond1 ;cond1 routine

MOV r4,r0 ; min = a

cond2 ;cond2 routine

MOV r4,r1 ;min = b

END