Answer:
40
Step-by-step explanation:
Calculations:
Let q²= homozygous recessive
p²= homozygous dominant
2 pq heterozygous
q² for this population is 640/1000 = 0.64
q = √o.64 = 0.8
so, P= 1- q
= 1- 0.8 = 0.2
The homozygous dominant frequency = p² = (0.2)(0.2) = 0.04
Therefore, you can expect 4% of 1000, or 40 individuals, to be homozygous dominant.