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A corporation with several thousand employees wants to estimate the mean commute time for all employees. They would like to construct a 95% confidence interval with a margin of error of no more than 4 minutes. Preliminary interviews with a small sample suggest that a reasonable estimate of the population standard deviation is σ = 10 minutes. Which of the following is the smallest sample the company can take to achieve the desired margin or error?

A.5
B.24
C.25
D.41
E.42

User Muzahid
by
5.0k points

1 Answer

6 votes

Answer:

C.25

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1-0.95)/(2) = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of
1-\alpha.

So it is z with a pvalue of
1-0.025 = 0.975, so
z = 1.96

Now, find the margin of error M as such


M = z*(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.

Which of the following is the smallest sample the company can take to achieve the desired margin or error?

This is n when
\sigma = 10, M = 4


M = z*(\sigma)/(√(n))


4 = 1.96*(10)/(√(n))


4√(n) = 1.96*10


√(n) = (1.96*10)/(4)


(√(n))^(2) = ((1.96*10)/(4))^(2)


n = 24.01

We have to round up.

So the correct answer is:

C.25