Question

A traveling sinusoidal electromagnetic wave in vacuum has an electric field amplitude of 83.7 V/m. Find the intensity of this wave and calculate the energy flowing during 15.5 s through an area of 0.0225 m2 that is perpendicular to the wave\'s direction of propagation.

Answer 1

Answer with Explanation:

We are given that

Electric field,E=83.7V/m

Time,t=15.5 s

Area,A=
`0.0225m^2`

We have to find the intensity of the wave and energy .

Intensity,I=
`(1)/(2)c\epsilon_0E^2`

Where
`c=3* 10^8m/s`

`\epsilon_0=8.85* 10^(-12)`

Substitute the values

`I=(1)/(2)(3* 10^8* 8.85* 10^(-12)* (83.7)^2)=9.3W/m^2`

Energy,
`E=IAt`

Substitute the values

`E=9.3* 0.0225* 15.5=3.24 J`