Question

Solve x^2+4x+8. What is the vertex?

Answer 1

`(-2,4)`

Explanation:

Well to start with there is a vertex formula which is
`-(b)/(2a) =h\\`,
`f(h)`

Your initial equation is
`x^2+4x+8` where
`ax^2+bx+c`. So you would plug in your numbers
`-(4)/(2(1))`
`=-(4)/(2) =-2` we know know that
`h=-2` so plug in h in
`f(-2)` which would be (-2)^2+4(-2)+8 = 4-8+8 = 4 which would make the vertex
`(-2,4)`