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Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and the sample size. Round the answer to the nearest thousandth where appropriate. muequals25​, sigmaequals7​, nequals15

User Mike Finch
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Answer:


\bar X= \mu = 25


\sigma_(\bar X)= (7)/(√(15))= 1.807

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the following conditions

Where
\mu=25 and
\sigma=7

And for this case we select a sample size of n= 15. and we want to know the distribution for the sample mean
\bar X. We can assume that the distribution for
\bar X is approximately normal and given by:


\bar X \sim N(\mu, (\sigma)/(√(n)))

Asuming that the distribution for X is also approximately normal. So then the parameters are:


\bar X= \mu = 25


\sigma_(\bar X)= (7)/(√(15))= 1.807

User Folkmann
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