Answer:
The diameter to be used is 0.98 cm
Step-by-step explanation:
The Poiseuille´s law is equal to:

Where
Q = flow rate = 0.015 kg/min = 2.5x10⁻⁷m³/s
P = pressure difference = 25 Pa
r = radius
η = viscosity = 230 cP = 0.23 Pa s
L = length of the tube = 10 cm = 0.1 m
Clearing r:
![r=\sqrt[4]{(8\eta LQ)/(\pi P) } =\sqrt[4]{(8*0.23*0.1*2.5x10^(-7) )/(\pi *25) } =0.0049m](https://img.qammunity.org/2021/formulas/engineering/college/kecg8zs7j2nzsdegv8yjv7m0q9clua47ny.png)
The diameter is:
